Ronald hat geschrieben:Auch das ist richtig, östlich von Risoer
Ronald hat geschrieben:Das ist vollkommen korrekt!!
<figure role="group">
<div id="map" style="width: 100%; height: 600px;"></div>
<figcaption>Bilderrätsel 2552</figcaption>
</figure>
<script>
// Unterschiedliche Karten
var OpenStreetMapLink = '<a href="https://openstreetmap.org">OpenStreetMap</a>',
OpenTopoMapLink = '<a href="https://opentopomap.org/">OpenTopoMap</a>';
var OpenStreetMapUrl = 'https://{s}.tile.openstreetmap.org/{z}/{x}/{y}.png',
OpenStreetMapAttrib = '© ' + OpenStreetMapLink + ' Contributors',
OpenTopoMapUrl = 'https://{s}.tile.opentopomap.org/{z}/{x}/{y}.png',
OpenTopoMapAttrib = '© ' + OpenTopoMapLink + ' Contributors';
var OpenStreetMapMap = L.tileLayer(OpenStreetMapUrl, {attribution: OpenStreetMapAttrib}),
OpenTopoMapMap = L.tileLayer(OpenTopoMapUrl, {attribution: OpenTopoMapAttrib});
var map = L.map('map', {
fullscreenControl: true,
layers: [OpenStreetMapMap] }); // only add one!
var baseLayers = {
"OSM Mapnik": OpenStreetMapMap,
"Topography": OpenTopoMapMap
};
// Mit metrischem Maßstab
L.control.scale({
imperial: false
}).addTo(map);
var pStavanger = [58.9663, 5.7246];
var pDummy1 = [58.9663, 10];
var pArendal = [58.4645, 8.7701];
var pDummy2 = [60, 8.7701];
var pRisoer = [58.7207522, 9.2343838];
var pDummy3 = [60, 9.2343838];
var pKristiansand = [58.147, 7.9937];
L.marker(pStavanger).addTo(map).bindPopup('Stavanger');
L.marker(pKristiansand).addTo(map).bindPopup('Kristiansand');
L.marker(pArendal).addTo(map).bindPopup('Arendal');
L.marker(pRisoer).addTo(map).bindPopup('Risør');
L.polyline([pStavanger, pDummy1], { color: 'blue', weight: 6 }).addTo(map);
L.polyline([pStavanger, pKristiansand], { color: 'red', weight: 6 }).addTo(map);
L.polyline([pArendal, pDummy2], { color: 'green', weight: 6 }).addTo(map);
L.polyline([pRisoer, pDummy3], { color: 'yellow', weight: 6 }).addTo(map);
L.control.layers(baseLayers).addTo(map);
var bMinimumBounds = [pStavanger, pKristiansand];
map.fitBounds(bMinimumBounds, { padding: [50, 50] });
</script>
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